
Originally Posted by
darryl
As far as the chip driving the bases of the driver transistors, the base current will not increase beyond normal because the emitter voltage also rises as the transistor conducts. The emitter will actually rise to a point where the transistor ceases to conduct when the gate capacitances have charged up to the voltage available from the output of the regulator. Base current in Q1 will drop to 0 even though there may be 12v on the base. The same thing happens with Q2, but in reverse voltage as the drive voltage from the chip swings to 0.