Math not being my strong suit, could anyone either point out where I can find the formula or tell me what it is please. I am turning down a piece of material to make a solid spacer for a suspension part and it would be certainly faster to set the angle once than to trial and error it. Thanks, Jim
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formula for determining angle between two known dimensions
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Originally posted by jmm03 View PostMath not being my strong suit, could anyone either point out where I can find the formula or tell me what it is please. I am turning down a piece of material to make a solid spacer for a suspension part and it would be certainly faster to set the angle once than to trial and error it. Thanks, Jim

I think he may be making a tapered cylinder and wants to know the half angle to set the compound.
If D1 is the diameter of the large end and D2 the diameter of the small end and these two diameters are separated by a length 'L', then the included half angle is arctangent [(D1D2) / (2*L) ]Regards, Marv
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Originally posted by jmm03 View PostThanks guys, if I am reading mklotz's formula correctly do I need to consult the trig table in machinery's handbook to obtain the angle in degree's? (his description of what I am doing is correct) JimRegards, Marv
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Originally posted by jmm03 View PostThanks guys, if I am reading mklotz's formula correctly do I need to consult the trig table in machinery's handbook to obtain the angle in degree's? (his description of what I am doing is correct) Jim
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Originally posted by jmm03 View PostThanks guys, if I am reading mklotz's formula correctly do I need to consult the trig table in machinery's handbook to obtain the angle in degree's? (his description of what I am doing is correct) Jim
1.5 1.0=.5
.5/ (2x5) = 0.0500
on a calculator: arctan .05 = 2.8624 degrees or 2 degrees 51 minutes 44.66 seconds
Looking down the sine column in the handbook 0.05001 is sine for 2 degrees 52 minutes
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If the specified length is the axial length, you need to use the tangent. If the specified length is the slope length (i.e., along the taper), use the sine tables.
For small angles, sine and tangent are almost but not quite the same figure, since the hypotenuse and the adjacent side of the triangle are almost the same length.
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Originally posted by Mike Burch View PostIf the specified length is the axial length, you need to use the tangent. If the specified length is the slope length (i.e., along the taper), use the sine tables.
For small angles, sine and tangent are almost but not quite the same figure, since the hypotenuse and the adjacent side of the triangle are almost the same length.
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Originally posted by jmm03 View PostThanks guys, if I am reading mklotz's formula correctly do I need to consult the trig table in machinery's handbook to obtain the angle in degree's? (his description of what I am doing is correct) Jim
Chilliwack BC, Canada
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Originally posted by BCRider View Post
Not only can you easily download a full scientific calculator with trig functions for your phone but assuming you typed your post on a Windows operating system then you have a full scientific calculator included. Just bring up the calculator and up in the top left corner click on the three lines (Win 10) and all your options for calculating will appear as a list box.
It has some things that most of those builtin calculators don't have...
Switchable between RPN and algebraic mode (although I can't imagine why anyone would use the latter)
Is fully PROGRAMMABLE (just like the one HP sells)
The onscreen window looks just like the real calculator, so, using the emulator, will get you in shape for using the real thing, should you buy one (~$60).
Highly recommended!
Regards, Marv
Home Shop Freeware  Tools for People Who Build Things
http://www.myvirtualnetwork.com/mklotz
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Originally posted by tom_d View Post
mklotz's formula is correct, and yes, you will find the angle in the trig tables. Doing the calculation electronically you would return the arctan function of the number in the formula. To find the angle in the trig tables look in the Sine column. The Machinerys Handbook I have gives an example where the large diameter is 1.5" the small diameter is 1.0" and the distance is 5"
1.5 1.0=.5
.5/ (2x5) = 0.0500
on a calculator: arctan .05 = 2.8624 degrees or 2 degrees 51 minutes 44.66 seconds
Looking down the sine column in the handbook 0.05001 is sine for 2 degrees 52 minutes
Right!! Many ways to skin a ca.... JR
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