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who can solve for X on this math problem

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  • who can solve for X on this math problem


  • #2
    You would have to know what the standard milling machine taper is or the diameter of the small end of the taper to get an answer. At least I would.
    It's only ink and paper

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    • #3
      Nope this is not that tough.

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      • #4
        Solve for X

        The taper is probably 3 1/2" per foot but that is just an assumption and we all know what happens when we assume.

        But, if you are going to solicit help for a problem like this the least you could do is to post a decent picture or drawing of the problem. I, for one, can't read most of the dimensions on your picture so I can't, or maybe won't, help you out.

        Errol Groff
        Errol Groff

        New England Model Engineering Society
        http://neme-s.org/

        YouTube channel: http://www.youtube.com/user/GroffErrol?feature=mhee

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        • #5
          I can't see an answer.

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          • #6
            solicit help for a problem
            He's quizzing us. That diagram is from '98

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            • #7
              If I read the dimensions correctly the solution is

              4.5-(1.843+(2X1.237))=X
              4.5-(1.843+2.474)=X
              4.5-4.317=X
              0.183=X

              Cheers
              Z

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              • #8
                Solving for X would be a piece of cake if the figures were clear but I couldn't read them. Zoom in a little and use more light. Better yet, run the drawing through a scanner, crop, adjust contrast, and post that..

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                • #9
                  Originally posted by DocZ
                  If I read the dimensions correctly the solution is

                  4.5-(1.843+(2X1.237))=X
                  4.5-(1.843+2.474)=X
                  4.5-4.317=X
                  0.183=X

                  Cheers
                  Z
                  X should be a little less than 4.5. Look at the drawing. .183 is too small.

                  The big problem here is that the system is unconstrained, unless one thing- are we to assume the two diagonal lines touching the circle are parallel to the two lines describing the top left and bottom left edges?
                  You never learn anything by doing it right.

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                  • #10
                    Originally posted by DocZ
                    If I read the dimensions correctly the solution is

                    4.5-(1.843+(2X1.237))=X
                    4.5-(1.843+2.474)=X
                    4.5-4.317=X
                    0.183=X

                    Cheers
                    Z
                    Oh yea. you know whats up...

                    thanks...

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                    • #11
                      I still don't see how you can arrive at an answer without knowing the taper the ball sits in or the diameter of the small end.
                      It's only ink and paper

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                      • #12
                        Originally posted by DocZ
                        If I read the dimensions correctly the solution is

                        4.5-(1.843+(2X1.237))=X
                        4.5-(1.843+2.474)=X
                        4.5-4.317=X
                        0.183=X

                        Cheers
                        Z
                        Sorry I wasn't quite complete I should have used

                        4.5-(1.843+(2X1.237))=Y
                        4.5-(1.843+2.474)=Y
                        4.5-4.317=Y
                        0.183=Y

                        Then X=4.5-Y
                        X=4.5-0.183

                        X=4.317

                        Sorry for the confusion

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                        • #13
                          I think you're drawing an invalid conclusion about the left side of the circle. The mark you're using is measure the location of that bevel.

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                          • #14
                            Originally posted by tony ennis
                            I think you're drawing an invalid conclusion about the left side of the circle. The mark you're using is measure the location of that bevel.

                            not to mention when you go back and calculate the taper it comes out odd.

                            this can't be solved.

                            It seams like a typo type of deal, because w is easy to find.
                            -Dan S.
                            dans-hobbies.com

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                            • #15
                              "Standard milling machine taper". What does that mean? R8? Or one of many other "standard" tapers? Which one. The answer depends on what the taper is. It can not be calculated from the information on the print.
                              Paul A.
                              SE Texas

                              Make it fit.
                              You can't win and there is a penalty for trying!

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