Hello Group,

I should know the answer to this question but I am drawing a blank. I have a 240v 3* heating element that has a resistence of 15.5 ohms for each coil. I am wanting to use this element for a powder coating oven and will be building controls to be able to step the elements on and off at 240v 1*.

The long drawn out question here is what is the current draw if all 3 elements are on at the same time?

I know 240v / 15.5 = 15.48 A , so do I add the 3 element ohms to get 46.5 ohms then divide by 240v to get 5.16A or do I multiply the 15.48 x 3 to get 46.44A or do I do something else? I think this is where l'm missing it. What is option #3?

I will watch for the answers to fly in, I know this is a simple question but l'm just stumped. Looking forward to all your HELP !

Tx Mr fixit for the family

Chris

I should know the answer to this question but I am drawing a blank. I have a 240v 3* heating element that has a resistence of 15.5 ohms for each coil. I am wanting to use this element for a powder coating oven and will be building controls to be able to step the elements on and off at 240v 1*.

The long drawn out question here is what is the current draw if all 3 elements are on at the same time?

I know 240v / 15.5 = 15.48 A , so do I add the 3 element ohms to get 46.5 ohms then divide by 240v to get 5.16A or do I multiply the 15.48 x 3 to get 46.44A or do I do something else? I think this is where l'm missing it. What is option #3?

I will watch for the answers to fly in, I know this is a simple question but l'm just stumped. Looking forward to all your HELP !

Tx Mr fixit for the family

Chris

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